Determine the power of the engine that evenly lifts a 5kg load to a height of 0.6m in 2 seconds.

Engine power can be calculated using the formula:
P = A / t, where P is the required engine power (W), A is the perfect work when lifting the load (A = Ft * h, where Ft is the gravity acting on the load (Ft = m * g, where m is the mass of the load) (m = 5 kg), g is the acceleration of gravity (we take g = 10 m / s²)), h is the height of the load (h = 0.6 m)), t is the time of the load (t = 2 s).
Let’s calculate the power of the load:
P = A / t = m * g * h / t = 5 * 10 * 0.6 / 2 = 15 W.
Answer: The motor power is 15 W.