Determine the power of the engine, which evenly raises 5 liters of water in a bucket weighing 1 kg

Determine the power of the engine, which evenly raises 5 liters of water in a bucket weighing 1 kg to a height of 0.6 m in 2 s.

Given: V1 (volume of water lifted by the engine) = 5 l; m2 (bucket weight) = 1 kg; h (lifting height) = 0.6 m; t (engine running time) = 2 s.

SI system: V1 = 5 * 10-3 m3.

Constants: g (acceleration due to gravity) ≈ 10 m / s2; ρw (density of water in a bucket) = 1000 kg / m3.

Solution: Let us determine the formula for calculating the power of the engine under consideration: N = A / t = ΔEp / t = m * g * h / t = (m1 + m2) * g * h / t = (V1 * ρw + m2) * g * h / t.

Calculation: N = (5 * 10-3 * 1000 + 1) * 10 * 0.6 / 2 = 18 W.