Determine the power of the engine with the help of which 20 tons of load are lifted to a height

Determine the power of the engine with the help of which 20 tons of load are lifted to a height of 25 m in 10 minutes, if the efficiency is 60%.

m = 20 t = 20,000 kg.

g = 10 m / s2.

h = 25 m.

t = 10 min = 600 s.

Efficiency = 60%.

Nsatr -?

Let us express the efficiency coefficient of the installation efficiency according to the formula: efficiency = Apol * 100% / Azatr.

Let us express the useful work of Apol by the formula: Apol = m * g * h.

The expended work of the Azat engine is expressed by the formula: Azat = Nzatr * t.

Efficiency = m * g * h * 100% / Nzatr * t.

Nzatr = m * g * h * 100% / efficiency * t.

Nzatr = 20,000 kg * 10 m / s2 * 25 m * 100% / 60% * 600 s = 13888.9 W.

Answer: the engine power is Nzatr = 13888.9 W.