The interaction of solutions of copper sulfate 2 and sodium hydroxide precipitated 19.6 g of copper hydroxide

| February 26, 2021 | education

The interaction of solutions of copper sulfate 2 and sodium hydroxide precipitated 19.6 g of copper hydroxide 2 precipitate. What amount of the starting material was contained in the solutions taken for the reaction?

CuSO4 + 2NaOH = Cu (OH) 2 + Na2SO4.

Determine the amount of copper hydroxide substance.

M (Cu (OH) 2) = 98 g / mol.

n = m / M = 19.6 g / 98 g / mol = 0.2 mol.

Draw up the proportions. Determine the amount of copper sulfate substance.

X mol of copper sulfate – 0.2 mol of copper hydroxide.

1 mol – 1 mol.

Let’s define x.

X = 1 * 0.2 / 1 = 0.2 mol.

This means that the amount of copper sulfate substance is 0.2 mol.

Determine the amount of sodium hydroxide substance.

X mol of sodium hydroxide is 0.2 mol of copper hydroxide.

2 mol – 1 mol.

X = 2 * 0.2 / 1 = 0.4 mol.

This means that the amount of sodium hydroxide substance is 0.4 mol.

Answer: 0.2 mol and 0.4 mol.



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