Determine the pressure exerted by water 80 cm high on the bottom of the samovar?
| August 7, 2021 | education
Initial data: h (water level in the samovar) = 80 cm (0.8 m).
Reference data: g (acceleration due to gravity) ≈ 10 m / s2; by the condition ρ (density of water in the samovar) = 1000 kg / m3.
The pressure that water will exert on the bottom of the samovar is determined by the formula: P = ρ * g * h.
Calculation: P = 1000 * 10 * 0.8 = 8000 Pa (8 kPa).
Answer: At the bottom of the samovar, water exerts a pressure of 8 kPa.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
