Determine the pressure exerted by water 85 cm high on the bottom of the samovar.

Determine the pressure exerted by water 85 cm high on the bottom of the samovar. Determine the force with which the water exerts pressure on the tap, with an area of 2 cm2 The density of water is 1000 kg / m3.

Pressure on the bottom of the samovar

P = q * h = 1000 * 0.85 = 850 kg / m2 = 0.085 kg / cm2.

We translate the area of the crane in m2

S = 2.2 / 100000 = 0.00022 m2.

Valve pressure

F = P * S * g = 850 * 0.00022 * 9.8 = 1.83 N.

Answer: pressure on the bottom of the samovar is 0.085 kg / cm2; pressure force on the valve 1.83 N.