Determine the pressure in the mine at a depth of 240 meters. The pressure on the Earth’s surface is 101.3 kPa.

Data: h (depth of a given shaft) = 240 m; P1 (pressure at the surface of the earth) = 101.3 kPa (101.3 * 10 ^ 3 Pa).

Reference values: g (acceleration due to gravity) = 9.81 m / s2; ρw (air density under normal conditions) = 1.225 kg / m3.

We express the pressure at a depth of 240 m from the equality: P2 – P1 = ρw * g * Δh, whence P2 = ρw * g * Δh + Р1.

Let’s do the calculation: P2 = 1.225 * 9.81 * 240 + 101.3 * 10 ^ 3 = 104184.14 Pa.

Answer: At a depth of 240 m, the pressure should be 104,184.14 Pa or 781.45 mm Hg. Art.