Determine the pressure of 4 kg of oxygen in a vessel with a capacity of 2 ^ 3 m.

Determine the pressure of 4 kg of oxygen in a vessel with a capacity of 2 ^ 3 m. Oxygen temperature 29. Molar mass 0.032 kg / mol.

m = 4 kg.

V = 2 m3.

t = 29 ° C.

M = 0.032 kg / mol.

R = 8.31 m2 * kg / s2 * K * mol.

P -?

For oxygen, we write the Mendeleev-Cliperon equation: P * V = m * R * T / M, where P is the gas pressure, V is the gas volume, m is the gas mass, R is the universal gas constant, T is the absolute temperature, M is the molar mass of gas.

P = m * R * T / M * V.

We find the absolute temperature by the formula: T = t + 273.

T = 29 ° C + 273 = 302 ° K.

P = 4 kg * 8.31 m2 * kg / s2 * K * mol * 302 ° K / 0.032 kg / mol * 2 m3 = 156851 Pa.

Answer: the oxygen pressure is P = 156851 Pa.