Determine the pressure of 4 kg of oxygen in a vessel with a capacity of 2 m3.
Determine the pressure of 4 kg of oxygen in a vessel with a capacity of 2 m3. The oxygen temperature is 29 ° C, the molar mass is 0.032 kg / mol.
m = 4 kg.
V = 2 m ^ 3.
t = 29 ° C.
T = 302 ° C.
R = 8.31 m ^ 2 * kg / s ^ 2 * K * mol.
M = 0.32 kg / mol.
P -?
Let us write the Mendeleev-Cliperon equation for oxygen: P * V = m * R * T / M, where P is the gas pressure, V is the gas volume, m is the gas mass, R is the universal gas constant, T is the absolute temperature, M is the molar mass of oxygen.
We find the absolute temperature by the formula: T = 273 + t.
We find the gas pressure by the formula: P = m * R * T / M * V.
P = 4 kg * 8.31 m ^ 2 * kg / s ^ 2 * K * mol * 302 ° K / 0.32 kg / mol * 2 m ^ 3 = 15685 Pa.
Answer: the oxygen pressure is P = 15685 Pa.