Determine the pressure of 4 kg of oxygen in a vessel with a capacity of 2 m3.

Determine the pressure of 4 kg of oxygen in a vessel with a capacity of 2 m3. The oxygen temperature is 29 ° C, the molar mass is 0.032 kg / mol.

m = 4 kg.

V = 2 m ^ 3.

t = 29 ° C.

T = 302 ° C.

R = 8.31 m ^ 2 * kg / s ^ 2 * K * mol.

M = 0.32 kg / mol.

P -?

Let us write the Mendeleev-Cliperon equation for oxygen: P * V = m * R * T / M, where P is the gas pressure, V is the gas volume, m is the gas mass, R is the universal gas constant, T is the absolute temperature, M is the molar mass of oxygen.

We find the absolute temperature by the formula: T = 273 + t.

We find the gas pressure by the formula: P = m * R * T / M * V.

P = 4 kg * 8.31 m ^ 2 * kg / s ^ 2 * K * mol * 302 ° K / 0.32 kg / mol * 2 m ^ 3 = 15685 Pa.

Answer: the oxygen pressure is P = 15685 Pa.



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