Determine the pressure of 4 kg of oxygen in a vessel with a capacity of 2 m3.

Determine the pressure of 4 kg of oxygen in a vessel with a capacity of 2 m3. Oxygen temperature 29 ° С, molar mass 0.032 kg / mol.

Initial data: m (mass of oxygen) = 4 kg; V (capacity of the oxygen vessel) = 2 m3; T (absolute temperature of oxygen in the vessel) = 29 ºС = 302 K.

Constants: R (universal gas constant) = 8.31 J / (mol * K); according to the condition M (molar mass of oxygen) = 0.032 kg / mol.

The oxygen pressure in the vessel can be determined using the Mendeleev-Clapeyron law: P * V = (m / M) * R * T, whence P = m * R * T / (V * M).

Let’s make the calculation: P = 4 * 8.31 * 302 / (2 * 0.032) = 156851.25 Pa ≈ 157 kPa.