Determine the pressure that acts in the sea on a person who dives to a depth of 18 meters

Determine the pressure that acts in the sea on a person who dives to a depth of 18 meters if the density of water in the sea is 1030 kg / m3

According to Pascal’s law:
The hydrostatic pressure inside the liquid at any depth does not depend on the shape of the vessel in which the liquid is located, and is equal to the product of the density of the liquid, the acceleration of gravity and the depth at which the pressure is determined:
P = ρ * g * h, where ρ is the density of the liquid, g is the free fall acceleration of a body raised above the Earth g = 9.8 m / s2, h is the depth of immersion in the liquid.
Let’s substitute the numerical values:
P = ρ * g * h = 1030 * 9.8 * 18 = 181692 Pa

Answer: pressure on a person in the sea is 181692 Pa.