Determine the pressure that the kerosene exerts on the bottom of a 5m2 tank. The mass of kerosene in a tank is 500 kg.

Given:

s = 5 square meters – tank bottom area;

ro = 800 kilograms / cubic meter – density of kerosene;

m = 500 kilograms is the mass of kerosene;

g = 10 Newton / kilogram – acceleration of gravity.

It is required to determine P (Pascal) – the pressure that kerosene exerts on the bottom of the tank.

Let’s find the volume of kerosene:

V = m / ro.

Then the height of the column of kerosene in the tank will be equal to:

h = V / s = m / (ro * s).

The pressure of kerosene at the bottom of the tank will be equal to:

P = ro * g * h = ro * g * m / (ro * s) = g * m / s;

P = 10 * 500/5 = 5000/5 = 1000 Pascal.

Answer: the pressure is 1000 Pascal.