Determine the relative molecular weight Feo mass fraction of Fe.

1) Relative molecular weight of FeO
Mr (FeO) = 56 + 16 = 72 (found using the periodic table).
2) W (Fe in FeO) = (Ar (element) x j (index) x 100%): Mr (substance)
Ar (Fe) = Mr (Fe) = 56
j (Fe) = 1
Mr (FeO) = 72
W (Fe) = (56 x 1 x 100%): 72 = 78%
Answer: Mr (FeO) = 72; W (Fe) = 78%



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