Determine the resistance, current strength and current power in this section

Determine the resistance, current strength and current power in this section of the circuit, if: R1 = 60 Ohm, R2 = 200 Ohm, R3 = 20 Ohm, R4 = 30 Ohm, U = 100 V.

Given:

R1 = 60 Ohm – the value of the first resistance in the circuit;

R2 = 200 Ohm – the value of the second resistance in the circuit;

R3 = 20 Ohm – the value of the third resistance in the circuit;

R4 = 30 Ohm – the value of the fourth resistance in the circuit;

U = 100 Volts – voltage in the electrical circuit.

It is required to determine R (Ohm) – the total resistance of the circuit section, I (Ampere) – the current strength and W (Watt) – the power in the circuit section.

Since the condition of the problem is not specified, we assume that all resistances are connected in series. Then, the total resistance will be equal to:

R = R1 + R2 + R3 + R4 = 60 + 200 + 20 + 30 = 310 ohms.

The current strength will be equal to:

I = U / R = 100/310 = 0.32 Amperes (the result has been rounded to one hundredth).

The power will be equal to:

W = U * I = 100 * 0.32 = 32 watts.

Answer: the resistance of the circuit section will be 310 ohms, the current strength is 0.32 Amperes, and the power is 32 watts.