Determine the resistance of the heating element of a boiler operating from a network with a voltage of 220 V

Determine the resistance of the heating element of a boiler operating from a network with a voltage of 220 V, if 578 kJ of energy has been released in the form of heat in 10 minutes of operation.

Task data: U (mains voltage) = 220 V; t (operating time of the boiler) = 10 minutes (in SI t = 600 s); Q (heat released in the boiler) = 578 kJ (578 * 10 ^ 3 J).

The resistance of the heating element of the boiler used can be determined using the Joule-Lenz law: Q = U2 * t / R, whence R = U ^ 2 * t / Q.

Let’s perform the calculation: R = 220 ^ 2 * 600 / (578 * 10 ^ 3) = 50.24 ohms.

Answer: The heating element of the boiler used has a resistance of 50.24 ohms.



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