Determine the resistivity of the conductor material if the voltage at the ends of the conductor is 0.85 V

| June 2, 2021 | education

Determine the resistivity of the conductor material if the voltage at the ends of the conductor is 0.85 V, the current in it is 8 A. The length of the conductor is 25m, the cross-sectional area is 4mm ^ 2 ..

U = 0.85 V.

I = 8 A.

L = 25 m.

S = 4 mm2.

ρ -?

We express the specific resistance of a cylindrical conductor ρ from the formula: R = ρ * L / S, where R is the resistance of the conductor, L is the length of the conductor, S is the cross-sectional area.

ρ = R * S / L.

We find the resistance of the conductor according to Ohm’s law for the section of the circuit: R = U / I, where U is the voltage at the ends of the conductor, I is the current in the conductor.

The formula for determining the resistivity ρ will take the form: ρ = U * S / L * I.

ρ = 0.85 V * 4 mm2 / 25 m * 8 A = 0.017 Ohm * mm2 / m.

According to the table of resistivity of substances, the material of the conductor is copper.

Answer: the resistivity of the conductor is ρ = 0.017 Ohm * mm2 / m.



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