Determine the root mean square velocity of air molecules at 17 degrees Celsius.

Determine the root mean square velocity of air molecules at 17 degrees Celsius. The molecular mass of air is 2.9 * 10 ^ -2 kg / mol?

Given: T (air temperature) = 17 ºС (absolute temperature is 290 K).

Constants: R (universal gas constant) = 8.31 J / (mol * K); according to the condition M (molecular weight of air) = 2.9 * 10-2 kg / mol.

You can determine the root mean square velocity of air molecules by the formula: υ = √ (3R * T / M).

Let’s calculate: υ = √ (3 * 8.31 * 290 / (2.9 * 10-2)) = 499.3 m / s.

Answer: Air molecules have a root mean square velocity of 499.3 m / s.