Determine the root mean square velocity of the oxygen molecules.
| April 9, 2021 | education
Task data: Patm. (normal atmospheric pressure) = 101 325 Pa; by condition ρ (oxygen density) = 1.43 kg / m3.
The mean square velocity of oxygen molecules can be determined by the formula: P = 1/3 * ρ * Vav ^ 2; Vav ^ 2 = 3P / ρ and Vav ^ 2 = √ (3P / ρ).
Product calculation: Vav = √ (3 * 101325 / 1.43) = 461 m / s.
Answer: Under normal conditions, the mean square velocity of oxygen molecules is 461 m / s.
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