Determine the specific heat capacity of brass if, when its rod weighing 400 g cools down to 20 ° C

Determine the specific heat capacity of brass if, when its rod weighing 400 g cools down to 20 ° C, an amount of heat equal to 3.2 kJ is released.

m = 400 g = 0.4 kg.

Δt = 20 ° C.

Q = 3.2 kJ = 3200 J.

C -?

The amount of heat Q, which is released during cooling of brass, is determined by the formula: Q = C * m * Δt, where C is the specific heat capacity of the substance, m is the mass of the rod, Δt is the change in the temperature of the rod.

Let us express the specific heat of brass from the formula: C = Q / m * Δt.

C = 3200 J / 0.4 kg * 20 ° C = 400 J / kg * ° C.

Answer: the specific heat capacity of brass is C = 400 J / kg * ° C.