Determine the specific heat of a metal body (iron) with a volume of 20 cm3, if its initial temperature is 25 degrees

Determine the specific heat of a metal body (iron) with a volume of 20 cm3, if its initial temperature is 25 degrees. He was dipped in hot oil at a temperature of 85 degrees. after a while, the temperature settled to 55 degrees.

Specific heat is determined by the heat release formula:
Q = c * m * (t2-t1) we get C = Q / (m * (t2-t1))
Substitute the values from the task:
specific gravity of iron 1 cm3 = 7.874g / cm3
m = 20 * 7.874 = 0.157kg
С = 152 / (0.157) * (55-25) = 152 / 4.71 = 32.73 J / kg ° С
Answer: С = 32.73 J / kg ° С