Problem data: m (mass of heated alcohol) = 500 g (0.5 kg); t1 (initial temperature of alcohol) = 22 ºС; t2 (final temperature of alcohol heating) = 32 ºС; Q (required amount of heat) = 12.5 kJ (12.5 * 10 ^ 3 J).
You can determine the specific heat of alcohol using the formula: Q = C * m * (t2 – t1), whence C = Q / (m * (t2 – t1)).
Calculation: C = 12.5 * 10 ^ 3 / (0.5 * (32 – 22)) = 2500 J / (kg * ºС).
Answer: The calculated specific heat of alcohol is 2500 J / (kg * ºС).
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