Determine the specific heat of silver, if an ingot weighing 160 g, when cooled from a temperature of 76 degrees

Determine the specific heat of silver, if an ingot weighing 160 g, when cooled from a temperature of 76 degrees to a temperature of 26 degrees, transferred an average amount of heat equal to 2 kJ

Initial data: m (weight of a silver ingot) = 160 g = 0.16 kg; t2 (initial ingot temperature) = 76 ºС, t1 (final ingot temperature) = 26 ºС, Q (amount of heat transferred by the ingot) = 2 kJ = 2000 J.

We express the specific heat capacity of silver from the formula:

Q = C * m * (t2 – t1) and C = Q / (m * (t2 – t1)).

Let’s perform the calculation:

C = 2000 / (0.16 * (76 – 26)) = 2000 / (0.16 * 50) = 250 J / (kg * K).

Answer: The specific heat of silver is 250 J / (kg * K).