Determine the stiffness of the spring if, under the action of a force of 150 N, it is stretched by 20 cm.
| June 26, 2021 | education
Initial data: F (value of the acting force) = 150 N; Δl (amount of tension (deformation) of the spring) = 20 cm = 0.2 m.
The spring rate can be determined according to Hooke’s law: F = Fcont. = k * Δl, whence k = F / Δl.
Let’s make a calculation: k = 150 / 0.2 = 750 N / m.
Answer: The stiffness of the spring under the given conditions is 750 N / m.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
