Determine the stiffness of the spring if, under the action of a force of 80 N, it lengthened by 5 cm.
| November 29, 2020 | education
F – strength
k – stiffness coefficient
x – spring extension
F = kx
k = F / x
F = 80 N
x = 5 cm = 0.05 m
k = 80 / 0.05 = 1600 N / m
When solving this problem, Hooke’s law was used
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