Determine the stiffness of the spring oscillating with a period of 3.14 s. The weight of the load on the spring is 0.1 kg.

univerkov | December 19, 2020 | education

Given:
m = 0.1kg
T = 3.14s
Find: k =?
Decision:
T = 2п \ / (m / k), squared to get rid of the root
T ^ 2 = 4n ^ 2 * (m / k)
k = (4mn ^ 2) / T ^ 2
k = 0.4 N / m
Answer: hardness is equal to k = 0.4 N / m

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