Determine the strength of the current passing through a straight conductor located in a uniform

Determine the strength of the current passing through a straight conductor located in a uniform magnetic field with an induction of 10 T, if a force of 20 N acts on the active part of a conductor 40 cm long. The conductor is located perpendicular to the lines of magnetic induction.

Given: V (induction of a uniform magnetic field) = 10 T; l (length of the active part of the straight conductor) = 40 cm (0.4 m); F (force acting on the active part of the conductor) = 20 N; the conductor is located perpendicular to the lines of induction and α = 90º (sinα = 1).

You can determine the strength of the current passing through a straight conductor from Ampere’s law: Fa = I * B * l * sinα; I = Fa / (B * l).

Calculation: I = 20 / (10 * 0.4) = 5 A.

Answer: The strength of the current passing through a straight conductor is 5 A.



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