Determine the strength of the current passing through the conductor if a force of 10n

Determine the strength of the current passing through the conductor if a force of 10n acts on the active part of the conductor 0.2m long at a magnetic induction of 20 T?

Given: l (length of the active part of the taken conductor) = 0.2 m; F (the force that acts on the active part of the conductor) = 10 N; B (value of magnetic induction) = 20 T; we take the angle α (the angle between the induction vector and the direction of the current) = 90º (sinα = sin 90º = 1).

The strength of the current passing through the conductor can be expressed from Ampere’s law: Fa = I * B * l * sinα; I = Fa / (B * l * sinα) = Fa / (B * l)

Calculation: I = 10 / (20 * 0.2) = 2.5 A.

Answer: The strength of the current passing through the conductor is 2.5 A.