Determine the temperature of the ammonia gas NH3, under a pressure of 2.1 * 10 ^ 5 Pa, if its volume is 0.02 m ^ 3

Determine the temperature of the ammonia gas NH3, under a pressure of 2.1 * 10 ^ 5 Pa, if its volume is 0.02 m ^ 3. and the weight is 0.03 kg.

Given: NH3
p = 2.1 * 10 ^ 5 Pa
V = 0.02 m ^ 3
m = 0.03kg
Find T-?
from the basic Mendeleev-Clayperon formula:
pV = (m / M) RT
M (NH3) = 0.017kg / mol
we derive the formula:
T = pVM / mR = (2.1 * 10 ^ 5 Pa * 0.02 m ^ 3 * 0.017kg / mol) / 0.03kg * 8.31 J / (mol K) = 286.4K
Answer: 286.4K



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