Determine the time during which the tram develops a speed of 36 km / h

Determine the time during which the tram develops a speed of 36 km / h, starting from a standstill with an acceleration of 0.2 m / s2.

Given:

v = 36 kilometers per hour = 10 meters per second – the speed that the tram developed over a certain period of time;

a = 0.2 meters per second squared – tram acceleration.

It is required to determine t (seconds) – a period of time.

Since, according to the condition of the problem, the tram starts to move, that is, its initial speed is zero (v0 = 0), in order to determine the time, it is necessary to use the following formula:

(v – v0) / t = a, from here we find:

t = (v – v0) / a = (10 – 0) / 0.2 = 10 / 0.2 = 50 seconds.

Answer: the tram will develop speed in 50 seconds.