Determine the V of hydrogen sulfide that is formed by the interaction of FeS with sulfuric acid if the yield

Determine the V of hydrogen sulfide that is formed by the interaction of FeS with sulfuric acid if the yield of the reaction products is 95%.

To solve the problem, we write down the equation, given by the condition:
V (l) -? W = 95%.
1. FeS + H2SO4 = FeSO4 + H2S – ion exchange reaction, gaseous hydrogen sulfide, iron sulfate is formed;
2. Let’s calculate the molar mass of the reaction product – Н2S:
M (H2S) = 34 g / mol;
3. Y (H2S) = 1 mol, which is confirmed by the equation.
4. Find the theoretical volume:
V (H2S) = 22.4 L, since 1 mole of any gas at n. y occupies a volume of 22.4 liters according to Avogadro’s law.
The practical volume is determined taking into account the product yield:
V (practical) = 0.95 * 22.4 = 21.28 liters.
Answer: hydrogen sulfide is released in a volume of 21.28 liters.