Determine the vibration frequency of a 400 g weight suspended on a spring with a stiffness of 160 Nm.

If the mass of the load exceeds the mass of the spring, the period of oscillation of the load on the spring can be calculated using the formula of the spring pendulum:

T = 2π (M / k) ^ 1/2,

where M is the mass of the cargo, M = 400 g = 0.4 kg; k is the stiffness of the spring, k = 160 N / m.

Oscillation period:

T = 2 × 3.14 × (0.4 / 160) ^ 1/2 = 0.314 s.

The frequency of oscillation of a load on a spring is a value inversely proportional to the period of oscillation:

ν = 1 / T = 1 / 0.314 = 3.185 s − 1 = 3.19 Hz.

Answer: 3.19 Hz.



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