Determine the voltage at the ends of a 20 m long nickel wire, if in 2 s through

Determine the voltage at the ends of a 20 m long nickel wire, if in 2 s through its cross section with an area of 1 mm2. 2.5 * 10 ^ 19 electrons pass.

Data: l (wire length) = 20 m; t (time of motion of electrons) = 2 s; S (wire cross-section) = 1 mm2; n (number of electrons passed) = 2.5 * 10 ^ 19 electrons.

Constants: ρ (specific resistance of nickel, 20 ºС) = 0.4 Ohm * mm2 / m; e (electron charge) = 1.6 * 10 ^ -19 C.

1) Amount of charge: q = n * e = 2.5 * 10 ^ 19 * 1.6 * 10 ^ -19 = 4 Cl.

2) Current strength: I = q / t = 4/2 = 2 A.

3) Wire resistance: R = ρ * l / S = 0.4 * 20/1 = 8 ohms.

4) Voltage: U = I * R = 2 * 8 = 16 V.