Determine the voltage at the ends of a steel wire 200 cm long and a cross-sectional area of 2 mm2

Determine the voltage at the ends of a steel wire 200 cm long and a cross-sectional area of 2 mm2, the current strength of which is 2A. (0.3V).

Let’s calculate the voltage at the ends of the steel wire according to Ohm’s law:

U = I * R, where I is the current in the steel wire (I = 2 A), R is the resistance of the steel wire (R = ρ * l / S, where ρ is the resistivity of the steel (ρ = 0.15 Ohm * mm2 / m), l is the length of the wire (l = 200 cm = 2 m), S is the cross-sectional area of the wire (S = 2 mm2)).

Let’s calculate the voltage at the ends of the steel wire:

U = I * R = I * ρ * l / S = 2 * 0.15 * 2/2 = 0.3 V.

Answer: The voltage at the ends of the steel wire is 0.3 V.