Determine the volume and mass of ammonia required to obtain 250 g of ammonium sulfate.

The reaction of ammonia with sulfuric acid is described by the following chemical reaction equation:
2NH3 + H2SO4 = (NH4) 2SO4;
To obtain one mole of ammonium sulfate, two moles of ammonia and one mole of sulfuric acid are required.
Determine the amount of substance in 250 grams of ammonium sulfate.
M (NH4) 2SO4 = (14 + 4) x 2 + 32 + 16 x 4 = 132 grams / mol;
N (NH4) 2SO4 = 250/132 = 1.894 mol;
To obtain this amount of salt substance, 1.894 x 2 = 3.788 mol of ammonia is required.
Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.
V NH3 = 3.788 x 22.4 = 84.8 liters;
Let’s find the mass of ammonia.
M NH3 = 14 + 3 = 17 grams / mol;
m NH3 = 3.788 x 17 = 64.4 grams;