Determine the volume (ml) occupied by 0.8 g of phosphorus (PH3) under normal conditions.

1. Find the chemical amount of phosphine:

n (PH3) = m (PH3): M (PH3);

M (PH3) = 31 + 3 * 1 = 34 g / mol;

n (PH3) = 0.8: 34 = 0.0235 mol;

2.Calculate the amount of phosphine:

V (PH3) = n (PH3) * Vm, Vm = 22.4 mol / dm3;

V (PH3) = 0.0235 * 22.4 = 0.5264 dm3 = 526.4 ml.

Answer: 526.4 ml.



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