Determine the volume of 70% and 30% solutions required to prepare 600 ml of 50% solution.
| February 14, 2021 | education
Let the volume of a 70% solution be x and the volume of a 30% solution y. It is necessary to prepare 600 ml of a 50% solution, which means:
x + y = 600
(x + y) * 50 = x * 70 + y * 30
Solving the system, we find that x = y = 300 ml.
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