Determine the volume of a 20% hydrochloric acid solution, with a density of 1.1, required

Determine the volume of a 20% hydrochloric acid solution, with a density of 1.1, required for the reaction with 10gr. calcium carbonate

The reaction of interaction of calcium carbonate with hydrochloric acid is described by the following chemical equation:

CaCO3 + 2HCl = CaCl2 + CO2 + H2O;

1 carbonate molecule interacts with 2 acid molecules.

Let’s calculate the available chemical amount of calcium carbonate.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 10.0 / 100 = 0.1 mol;

This reaction requires 0.1 x 2 = 0.2 mol of acid.

Let’s calculate its weight.

M HCl = 1 + 35.5 = 36.5 grams / mol;

m HCl = 0.2 x 36.5 = 7.3 grams;

The mass of a 20% solution will be 7.3 / 0.2 = 36.5 grams.

The volume of a solution with a density of 1.1 grams / cm3 will be equal to 36.5 / 1.1 = 33.2 cm3;