Determine the volume of a piece of iron whose mass is 900 grams.
| April 18, 2021 | education
Problem data: m (mass of a piece of iron taken) = 900 g (in SI m = 0.9 kg).
Reference values: ρzh (density of iron) = 7800 kg / m3.
The volume of a piece of iron taken will be equal to the ratio of its mass to density: V = m / ρzh.
Let’s make a calculation: V = 0.9 / 7800 = 1.15 * 10-4 m3 = 115 cm3.
Answer: A piece of iron weighing 900 grams has a volume of 115 cm3.
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