Determine the volume of acetylene that will be released when interacting with water

Determine the volume of acetylene that will be released when interacting with water calcium carbide weighing 400 g with a mass fraction of impurities of 2.5%.

When calcium carbide interacts with water, acetylene and calcium hydroxide are synthesized. The reaction is described by the following equation.
CaC2 + 2H2O = Ca (OH) 2 + C2H2;
From 1 mole of calcium carbide, 1 mole of acetylene is synthesized.
Let’s calculate the amount of calcium carbide substance available.
To do this, we divide the mass of the substance by its molar weight.
M CaC2 = 40 + 12 x 2 = 64 grams / mol;
N CaC2 = 400 x 0.975 / 64 = 6.094 mol;
Let’s calculate the volume of the same amount of acetylene.
To do this, multiply the amount of substance by the volume of 1 mole, which is 22.4 liters.
V C2H2 = 6.094 x 22.4 = 136.5 liters;