Determine the volume of air in liters required to burn 5.6 liters of ethylene.

univerkov | September 6, 2021 | education

Given:
V (C2H4) = 5.6 L

Find:
V (air) -?

1) C2H4 + 3O2 => 2CO2 + 2H2O;
2) V (O2) = V (C2H4) * 3 = 5.6 * 3 = 16.8 L;
3) V (air) = V (O2) * 100% / φ (O2) = 16.8 * 100% / 21% = 80 HP.

Answer: The air volume is 80 liters.

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