Determine the volume of ammonia obtained during the decomposition of 5.35 grams of ammonium chloride.

Solution:

Let’s write the reaction equation for the decomposition of ammonium chloride:
NH4Cl = HCl + NH3;

The relative atomic mass of nitrogen is 14, hydrogen is 1, chlorine is 35.5. This means that the molecular weight of ammonium chloride is:
14 + 4 + 35.5 = 53.5 g / mol;

Let’s find the amount of substance in ammonium chloride:
5.35 / 53.5 = 0.1 mol;

Ammonia is preceded by the same coefficient as before ammonium chloride. This means that the amount of substance in ammonia is 0.1 mol. Let’s find the volume of released ammonia:
22.4 * 0.1 = 2.24 liters;

Answer: the volume of ammonia obtained is 2.24 liters.