Determine the volume of carbon dioxide if calcium carbonate interacts

Determine the volume of carbon dioxide if calcium carbonate interacts with dilute nitric acid in the reaction, HNO3 is consumed, a chemical amount of 0.1 mol.

Let’s find the quantitative ratios of substances.

2НNО3 + СаСО3 = Са (NO3) 2 + H2О + СО2 ↑.

For 2 mol of НNО3 there is 1 mol of СО2.

Substances are in quantitative ratios of 2: 1.

The amount of CO2 is 2 times less than the amount of HNO3.

n (CO2) = ½ n (HNO3) = 0.1: 2 = 0.05 mol.

Let’s find the volume of CO2.

V = n Vn, where Vn is the molar volume of gas equal to 22.4 l / mol.

V = 0.05 mol × 22.4 L / mol = 1.12 L.

Answer: 1.12 liters.