Determine the volume of carbon dioxide obtained during the combustion of 100 g of ethanol?

The ethanol combustion reaction is described by the following chemical equation:

C2H5OH + O2 = 2CO2 + 3H2O;

1 molecule of alcohol interacts with one molecule of oxygen. In this case, 2 molecules of carbon dioxide are synthesized.

Let’s calculate the chemical amount of a substance in 100 grams of ethanol.

Its molar mass is:

M C2H5OH = 12 x 2 + 6 + 16 = 46.0 grams / mol;

N C2H5OH = 100.0 / 46.0 = 2.174 mol;

This will release 2.174 x 2 = 4.348 mol of carbon dioxide.

1 mole of ideal gas normally takes on a volume of 22.40 liters.

The amount of carbon dioxide will be:

V CO2 = 4.348 x 22.40 = 97.4 liters;

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