Determine the volume of carbon dioxide released during the combustion of heptanol weighing 7.2 g.

Let’s compose the reaction equation:
2С7Н15 – ОН + 21О2 = 14СО2 + 16Н2О – the combustion reaction of heptanol occurs with the release of carbon dioxide;
Determine the number of moles of heptanol if its m (C7H15 – OH) = 7.2 g;
Y (C7H15OH) = m (C7H15 – OH) / M (C7H15OH); Y (C7H15OH) = 7.2 / 116 = 0.062 mol;
Let’s make a proportion according to the reaction equation:
0.062 mol (C7H15OH) – X mol (CO2);
-2 mol -14 mol from here,
X mol (CO2) = 0.062 * 14/2 = 0.43 mol;
Let’s calculate the volume of CO2 according to Avogadro’s law:
V (CO2) = 0.43 * 22.4 = 9.6 liters.
Answer: during the combustion of heptanol, carbon dioxide was released in a volume of 9.6 liters.