Determine the volume of carbon monoxide (4), formed by dissolving 110 g of limestone containing 92% calcium

Determine the volume of carbon monoxide (4), formed by dissolving 110 g of limestone containing 92% calcium carbonate, in an excess of hydrochloric acid, you should get 22.67.

The reaction of calcium carbonate with hydrochloric acid synthesizes calcium chloride, water and gaseous carbon dioxide. The reaction is described by the following equation:

CaCO3 + 2HCl = CaCl2 + CO2 ↑ + H2O;

Let’s determine the chemical amount of calcium carbonate. To do this, divide its weight by its molar mass.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 110 x 0.92 / 100 = 1.012 mol;

1.012 mol of calcium carbonate will react with 1.012 x 2 = 2.024 mol of hydrochloric acid. This will release 1.012 mol of carbon dioxide.

Let’s calculate the volume that it occupies. To this end, we multiply the amount of substance by the volume of 1 mole of gas (filling 22.4 liters).

V CO2 = 1.012 x 22.4 = 22.67 liters;