Determine the volume of carbon monoxide (IV), which is formed during the decomposition of 250 g of calcium carbonate.

The reaction between calcium carbonate and sulfuric acid is described by the following chemical equation:

CaCO3 + H2SO4 = CaSO4 + CO2 + H2O;

1 carbonate molecule interacts with 1 acid molecule. This synthesizes 1 molecule of carbon dioxide.

Let’s calculate the amount of substance in 250 grams of calcium carbonate.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 250/100 = 2.5 mol;

The same amount of carbon dioxide will be synthesized.

1 mole of ideal gas normally takes a volume of 22.40 liters.

V CO2 = 2.5 x 22.40 = 56 liters;