Determine the volume of Cl required to form 120 g of a 15% HCl solution.

m (HCl) solution = 120 g.

W = 15%.

Determine the amount of chlorine needed. We write down the solution.

First, we write down the equation of reactions.

H2 + Cl2 = 2HCl.

We find the mass of hydrogen chloride. We use the following formula.

W = m r.v / m r-ra * 100%.

m r.v = W * m solution / 100% = 15 * 120/100 = 18 g.

Using the reaction equation, we find the mass of chlorine.

M (Cl2) = 35.5 * 2 = 71 g / mol.

M (HCl) = 1 + 35.5 = 36.5 g / mol.

X g Cl2 – 18 g HCl.

71 g / mol Cl2 – 36.5 g / mol HCl.

Find the unknown value of x.

X = 71 * 18: 36.5 = 35 g Cl2.

Find the amount of chlorine required for the reaction.

n = m / M.

n = V / Vm.

m / M = V / Vm.

V = m * Vm / M.

V = 35 * 22.4 / 71 = 11 liters.

Answer: V (Cl2) = 11 liters.