Determine the volume of ethylene obtained by dehydrogenation of 0.6 g of ethane.

Let’s make an equation, make calculations:
C2H6 + C2H4 + H2 – dehydrogenation reaction, ethylene was obtained;
M (C2H6) = 30 g / mol;
M (C2H4) = 28 g / mol.
Let’s determine the number of moles of ethane:
Y (C2H6) = m / M = 0.6 / 30 = 0.02 mol.
According to the equation, the number of moles of ethane and ethylene are equal to 1 mol, which means that Y (C2H4) = 0.02 mol.
Let’s calculate the volume of ethylene:
V (C2H4) = 0.02 * 22.4 = 0.448 l.
Answer: the volume of ethylene is 0.448 liters.