Determine the volume of gas formed by the interaction of magnesium carbonate with 160 g

Determine the volume of gas formed by the interaction of magnesium carbonate with 160 g of a solution containing 20% hydrochloric acid.

Magnesium carbonate reacts with hydrochloric acid. In this case, magnesium chloride is synthesized and gaseous carbon dioxide is released. The reaction is described by the following equation:

MgCO3 + 2HCl = MgCl2 + H2O + CO2 ↑;

Let’s calculate the chemical amount of hydrochloric acid.

To do this, divide the weight of the acid by the weight of 1 mole of acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 160 x 0.2 / 36.5 = 0.8767 mol;

With this amount of acid, 0.8767 / 2 = 0.438 mol of carbon dioxide will be synthesized.

Let’s calculate its volume.

To do this, multiply the volume of 1 mole of gas (which is 22.4 liters) by the amount of substance.

V CO2 = 0.438 x 22.4 = 9.81 liters;