Determine the volume of gas that is formed by the interaction of 31.6 g of K sulfite with hydrochloric acid.

Given:
m (K2SO3) = 31.6g
Find: V (gas) -?
Decision:
K2SO3 + 2HCl = 2KCl + SO2 ↑ + H2O
n (K2SO3) = m / M = 0.2 mol
n (K2SO3) = n (SO2) = 0.2 mol
V (SO2) = nVm = 4.48L



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